Answer:
49152
Step-by-step explanation:
The n th term of a geometric sequence is
[tex]a_{n}[/tex] = a₁ [tex]r^{n-1}[/tex]
where a₁ is the first term and r the common ratio
Here a₁ = 3 and r = [tex]\frac{-6}{3}[/tex] = - 2 , then
a₁₅ = 3 × [tex](-2)^{14}[/tex] = 3 × 16384 = 49152
