Respuesta :
Given:
One side = 8x-10
Another side = 2(x+1)
To find:
The perimeter of the pentagon.
Solution:
We know that, all five sides of a regular pentagon are equal.
[tex]8x-10=2(x+1)[/tex]
[tex]8x-10=2x+2[/tex]
[tex]8x-2x=10+2[/tex]
[tex]6x=12[/tex]
Divide both sides by6.
[tex]x=2[/tex]
Now, the length of each side of the pentagon is
[tex]Side=8(2)-10[/tex]
[tex]Side=16-10[/tex]
[tex]Side=6[/tex]
We know that, perimeter of a regular pentagon is
[tex]P=5a[/tex]
Where, a is the side length.
[tex]P=5(6)[/tex]
[tex]P=30[/tex]
Therefore, the perimeter of the regular pentagon is 30 units.
