Answer:
K₅Mn₅O₁₆
Explanation:
From the question given above, the following data were obtained:
Potassium (K) = 27.5 %
Manganese (Mn) = 37.5 %
Oxygen (O) = 35 %
Empirical formula =?
The empirical formula for the compound can be obtained as follow:
K = 27.5 %
Mn = 37.5 %
O = 35 %
Divide by their molar mass
K = 27.5 / 39 = 0.705
Mn = 37.5 / 55 = 0.682
O = 35 / 16 = 2.188
Divide by the smallest
K = 0.705 / 0.682 = 1
Mn = 0.682 / 0.682 = 1
O = 2.188 / 0.682 = 3.2 = 32/10 = 16/5
K = 1
Mn = 1
O = 16/5
Multiply by 5 to express in whole number
K = 1 × 5 = 5
Mn = 1 × 5 = 5
O = 16/5 × 5 =16
Thus, the empirical formula for the compound is K₅Mn₅O₁₆
