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The resistance, R (in ohms), of a wire varies
directly with the length, L (in cm), of the
wire, and inversely with the cross-sectional
area, A (in cm2). A 500 cm piece of wire with
a radius of 0.2 cm has a resistance of 0.025
ohm. Find an equation that relates these
variables.

Respuesta :

Answer:

The equation is: [tex]R = \frac{L}{A}[/tex]

Step-by-step explanation:

The resistance, R (in ohms), of a wire varies directly with the length, L (in cm), of the wire, and inversely with the cross-sectional area, A (in cm2).

This means that we want to find an equation for R, which is a fraction.

Since it varies directly with the length L, L is the numerator.

Since it varies inversely with the cross-sectional area, A is the denominator.

So the equation is:

[tex]R = \frac{L}{A}[/tex]

Answer:

R ∝ L/ A

R = K L/ A

0.025= 500K/0.126

the constant, K=6.3 X 10^-6

Step-by-step explanation:

Step 1

The resistance, R (in ohms), of a wire varies directly with the length, L (in cm), of the wire, and inversely with the cross-sectional

area, A (in cm2)  is written mathematically as

R ∝ L/ A

Introducing the constant of proportionality,K,  we have

R = K L/ A

So given that s  500 cm piece of wire with  a radius of 0.2 cm has a resistance of 0.025 ohm.

We would First find area , since radius was given

Area = πr²

= 3.142 x 0.2²= 0.126cm²

Step 2

With our equation , R = K L/ A, puting all the necessary variables, we have

R = K L/ A

0.025= 500K/0.126

Solving for K

0.025= 500K/ 0.126

(0.025 X 0.126)/500 = K

K=6.3 X 10^-6