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hydrogen peroxide can decompose to water and oxygen by the following reaction

2H2O2 (l) ------ 2H2O(l) + O2(g) enthalpy=-196kj
calculate the value of q when 5.00g of h20(l) decomposes at constant pressure.

Respuesta :

antonsandiego
To begin calculating, there is one thing you need to remember :[tex]1 mole of H2O2=34.0148 g[/tex]
Then we have [tex]5.00g of H2O2=5/34.0148=0.146995[/tex]
As you know decomposition of 2moles now has prodused 196kj
So, q is made due [tex]0.146995 moles of H2O2[/tex][tex]=(-196/2)*0.146995=-14.40551Kj[/tex]
I'm sure it will help.

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