contestada

the sum of 4 consecutive integers is 198. What is the fourth number in this sequence.

Respuesta :

let x, x+1,x+2, x +3 are the numbers
so
x + x +1 + x +2 +x +3 = 198
4x + 6 = 198
4x =198-6
4x = 192
 x = 192/4
 x = 48
 x + 1 = 48 + 1 = 49
 x + 2 = 48 + 2 = 50
 x + 3 = 48 + 3 = 51

proof
48 + 49 + 50 + 51 = 198

so the numbers are 48, 49, 50, 51

fourth number in this sequence is 51