The question is below thanks

Answer:
AC = 49
Step-by-step explanation:
Using the Altitude - on - Hypotenuse theorem
(leg of large Δ )² = (part of hypotenuse below it ) × (whole hypotenuse)
BC² = DC × AC, substitute values
14² = 4 × x
196 = 4x ( divide both sides by 4 )
49 = x
Thus AC = x = 49
Step-by-step explanation:
pythogoream theorem.(hyp^2=opp^2+adj^2)
hyp=14 adg=4 opp=?
since we have to find opp
opp^2=hyp^2-adj^2
opp^2=14^2-4^2
196-16=180
[tex] \sqrt{180} [/tex]
BD= 13.41
(Q as theta)
sinQ= opp÷hyp
= 13.41÷14
Q=sin^-1(13.4÷14)
Q=73.33
cosQ=adj(AD)÷hyp(BC)
cos 73.33× 14 =adj
AD=4.01
Therefore, AC =AD +DC(4.01+4)
=8.01
I am not sure....but I got this much