goldyprincess227
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Consider the function f(x) = (x+ 1)2 - 1. Which of the following functions stretches
fo) vertically by a factor of 4?
O A) f0 - (/ax+ 1)2 +3
O B) f9 = 1/ax+ 1)2 -4
Oo fo-4(x+ 1)2 - 1
OD) fo = 4(4x+ 1)2- 1

Consider the function fx x 12 1 Which of the following functions stretches fo vertically by a factor of 4 O A f0 ax 12 3 O B f9 1ax 12 4 Oo fo4x 12 1 OD fo 44x class=

Respuesta :

Answer:

C

Step-by-step explanation:

A coefficient of 4 would have to be added in front of (x+1)^2 in order to vertically stretch the function by a factor of 4.

The answer that demonstrates this is choice C: [tex]f(x) = 4(x+1)^2-1[/tex]

The functions stretches vertically by a factor of 4 will be f(x) = 4(x+ 1)² - 1. Then the correct option is C.

What is the equation of the parabola?

Let the point (h, k) is the vertex of the parabola and a is the leading coefficient.

Then the equation of the parabola will be given as,

y = a(x - h)² + k

The quadratic function is given below.

f(x) = a(x+ 1)² - 1

If the value of the leading coefficient lies between 0 to 1. Then the parabola is stretched horizontally.

And if the value of the leading coefficient is greater than one. Then the parabola is stretched vertically.

The functions stretches vertically by a factor of 4. Then the value of the leading coefficient is 4. Then the equation will be

f(x) = 4(x+ 1)² - 1

Then the correct option is C.

More about the equation of parabola link is given below.

https://brainly.com/question/20333425

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