Answer:
T = 171.59 hours
Explanation:
Mass of Ganymede, [tex]M=1.9\times 10^{27}\ kg[/tex]
Radius of the orbit, [tex]R=1.07\times 10^9\ m[/tex]
We need to find Ganymede's period. Let time is T. Using Kepler's third law of motion.
[tex]T^2=\dfrac{4\pi^2}{GM}r^3\\\\T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.9\times 10^{27}}\times (1.07\times 10^9)^3\\\\T=617754.35\ s[/tex]
or
T = 171.59 hours
Hence, Ganymede's period is 171.59 hours.
