Moles of O₂ = 3.92
Further explanation
Given
V=1 L
T=-118 °C + 273 = 155 K
P = 49.77 atm
Required
moles of O₂
Solution
the gas equation can be written
[tex]\large {\boxed {\bold {PV = nRT}}}[/tex]
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
Input the value :
n= PV/RT
[tex]\tt n=\dfrac{49.77~atm\times 1~L}{0.082\times 155}=3.92~moles[/tex]
