Answer:
v = 15 m / s
Explanation:
In this exercise we are given the position function
x = 5 t²
and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval
[tex]v= \frac{v_{f} - v_{o} }{t_{f} - t_{o} }[/tex]
let's look for the displacements
t = 0 x₀ = 0 m
t = 3 [tex]x_{f}[/tex] = 5 3 2
x_{f} = 45 m
we substitute
[tex]v = \frac{45 -0}{3 - 0}[/tex]
v = 15 m / s
