Answer:
[tex]\frac{1}{3}[/tex]
Step-by-step explanation:
Using the rule of exponents/ radicals
[tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex]
[tex]a^{\frac{1}{2} }[/tex] ⇔ [tex]\sqrt{a}[/tex]
Given
[tex]9^{-\frac{1}{2} }[/tex]
= [tex]\frac{1}{9^{\frac{1}{2} } }[/tex]
= [tex]\frac{1}{\sqrt{9} }[/tex]
= [tex]\frac{1}{3}[/tex]
