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An object is located 360 millimeters from a converging lens. The image formed is 150 millimeters high, at a distance of 90 millimeters from the lens. What’s the height of the object?

Respuesta :

ardni313

The height of the object : 600 mm

Further explanation

Given

d object=360 mm(object distance)

d image=90 mm(image distance)

Required

h object

Solution

focal length = f :

[tex]\tt \dfrac{1}{f}=\dfrac{1}{d_o}+\dfrac{1}{d_i}\\\\\dfrac{1}{f}=\dfrac{1}{360}+\dfrac{1}{90}\rightarrow f=72~mm[/tex]

The magnification :

[tex]\tt M=\dfrac{d_i}{d_o}=\dfrac{90}{360}=0.25[/tex]

[tex]\tt M=\dfrac{h_i}{h_o}\\\\0.25=\dfrac{150}{h_o}\rightarrow h_o=600~mm[/tex]

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