Answer:
The sum of the two vectors is 161.278 m.
Explanation:
Given;
vector, B = 101 m inclined at angle 60⁰
vector, A = 85 m inclined at angle 0⁰
Y-component of the vectors;
[tex]R_y = 101(sin \ 60^0) + 85(sin \ 0^0) =87.466 \ m[/tex]
X-component of the vectors;
[tex]R_x = 101(cos \ 60^0) + 85(cos \ 0^0)\\\\R_x = 50.5 + 85 = 135.5 \ m[/tex]
Sum of the two vectors;
[tex]R = A+ B\\\\R = \sqrt{R_y^2 + R_x^2} \\\\R = \sqrt{87.466^2 \ + \ 135.5^2} \\\\R = \sqrt{26010.55} \\\\R = 161.278 \ m[/tex]
Therefore, the sum of the two vectors is 161.278 m.
