Answer:
The vertical distance in feet that the plane traveled was 4 Km
Step-by-step explanation:
The Slope of a Line
Suppose we know a line passes across points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:
[tex]\displaystyle m=\frac{y_2-y_1}{x_2-x_1}[/tex]
The airplane ascent will be modeled with the equation of a line because we are given a constant slope of m=2/3. We also know the horizontal distances are x1=1 Km and x2=7 Km. Substituting in the formula above:
[tex]\displaystyle \frac{2}{3}=\frac{y_2-y_1}{7-1}[/tex]
Operating:
[tex]\displaystyle \frac{2}{3}=\frac{y_2-y_1}{6}[/tex]
Solving for y2-y1, we get the vertical distance traveled by the plane:
[tex]\displaystyle y_2-y_1=6*\frac{2}{3}=4[/tex]
Thus, the vertical distance in feet that the plane traveled was 4 Km
