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Given a manhole with the outlet invert elevation of 2605. A run of 48 inch pipe connects to the next manhole at an invert elevation of 2610. What is the distance between manholes if the correct pipe grade is 3%

Respuesta :

Answer:

Distance between manholes = 166.67 (Unit) (Approx)

Explanation:

Given:

Invert elevation = 2605

New Invert elevation = 2610

Grade % = 3% = 0.03

Find:

Distance between manholes

Computation:

Grade % = (Change in elevation)/Distance between objects

0.03 = (2610-2605)/Distance between manholes

0.03 = 5 / Distance between manholes

Distance between manholes = 166.67 (Unit) (Approx)

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