Respuesta :
Answer:
The answer is below
Explanation:
Avogadro stated that "Equal volumes of all gases at the same temperature and pressure contain the same number of molecules". Hence at standard temperature and pressure 1 mole of a gas occupies 22.4 liters of volume.
1 mol = 22.4 liters
Given a gas with 1 L and mass of 1.92 g at STP.
number of moles = 1 L / (22.4 L / mol) = 0.0446 mol
The molar mass = mass of gas / number of moles
molar mass = 1.92 g / 0.0446 mol
molar mass = 43.008 g / mol
The molar mass will be "43.008 g/mol".
Given:
- Mass = 1.92 g
- Sample of gas = 1.00 L
Now,
Number of moles will be:
= [tex]\frac{1 \ L}{22.4 \ L/mol}[/tex]
= [tex]0.446 \ mol[/tex]
hence,
The molar mass,
= [tex]\frac{Mass \ of \ gas}{Number \ of \ moles}[/tex]
By putting the values,
= [tex]\frac{1.92}{0.446}[/tex]
= [tex]43.008 \ g/mol[/tex]
Thus the answer above is correct.
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