Respuesta :

Answer:

The answer is below

Explanation:

Avogadro stated that "Equal volumes of all gases at the same temperature and pressure contain the same number of molecules". Hence at standard temperature and pressure 1 mole of a gas occupies 22.4 liters of volume.

1 mol = 22.4 liters

Given a gas with 1 L and mass of 1.92 g at STP.

number of moles = 1 L / (22.4 L / mol) = 0.0446 mol

The molar mass = mass of gas / number of moles

molar mass = 1.92 g / 0.0446 mol

molar mass = 43.008 g / mol

The molar mass will be "43.008 g/mol".

Given:

  • Mass = 1.92 g
  • Sample of gas = 1.00 L

Now,

Number of moles will be:

= [tex]\frac{1 \ L}{22.4 \ L/mol}[/tex]

= [tex]0.446 \ mol[/tex]

hence,

The molar mass,

= [tex]\frac{Mass \ of \ gas}{Number \ of \ moles}[/tex]

By putting the values,

= [tex]\frac{1.92}{0.446}[/tex]

= [tex]43.008 \ g/mol[/tex]

Thus the answer above is correct.

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