Answer:
16.8 seconds
Explanation:
Given that:
Constant speed of rabbit = 4.2 m/s
Initial Velocity (u) of cat = 0
Acceleration (a) of cat = 0.5 m/s²
Time it takes cat to catch rabbit ;
Using the relation:
Distance moved by rabbit (Dr) :
Dr = speed * time ; Dr = 4.2t
Distance moved by Cat (Dc) :
Dc = ut + 0.5at^2
Dc = 0 + 0.5at^2
Hence, Cat will catch rabbit when Dr = Dc
4.2t = 0.5at^2
4.2t = 0.5(0.5)t^2
4.2t = 0.25t^2
Divide both sides by t
4.2 = 0.25t
t = 4.2 / 0.25
t = 16.8 seconds
Hence, the cat will catch the rabbit after 16.8 seconds
