What is the equation of the line that passes through the point (4.11) and is perpendicular to the line with the following equation? OA. y = -x + 14 O B. - r - 15 OD. & 1 + 8​

Respuesta :

Answer:

[tex]y = x +7[/tex]

Step-by-step explanation:

Given

[tex]Point\ (x_1,y_1) = (4,11)[/tex]

Perpendicular to [tex]y = -x + 14[/tex]

Required

Determine the line equation

An equation has the form

[tex]y = mx + b[/tex]

Where

[tex]m = slope[/tex]

By comparison with [tex]y = -x + 14[/tex]

[tex]m = -1[/tex]

Because the line is perpendicular to [tex]y = -x + 14[/tex], the following relationship exists

[tex]m_1 = \frac{-1}{m}[/tex] i.e. the condition for perpendicularity

Where m1 is the slope of the equation that passes through [tex]Point\ (x_1,y_1) = (4,11)[/tex]

So, we have:

[tex]m_1 = \frac{-1}{-1}[/tex]

[tex]m_1 = 1[/tex]

The line equation is then calculated using:

[tex]y - y_1 = m_1(x - x_1)[/tex]

Where

[tex]m_1 = 1[/tex]

[tex]Point\ (x_1,y_1) = (4,11)[/tex]

So, we have:

[tex]y - 11 = 1(x - 4)[/tex]

[tex]y - 11 = x - 4[/tex]

Add 11 to both sides

[tex]y - 11+11 = x - 4+11[/tex]

[tex]y = x - 4+11[/tex]

[tex]y = x +7[/tex]

The B, C and D parts of your question are not clear.

Apply the same steps used in (a) above and you'll get your answers