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Calculate the magnitude and direction of the centripetal acceleration of the following objects moving in a circle:

A 2000 kg truck drives along a circular round a bout with a radius of 20 m at a constant speed of 10 m/s.

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absor201

Answer:

The magnitude and direction of the centripetal acceleration will be:

[tex]a_c=5[/tex] m/s²   (towards the center of the circle).

Explanation:

Given

  • v = 10 m/s
  • r = 20 m

Using the formula to determine the centripetal acceleration

[tex]a_c=\frac{v^2}{r}[/tex]

[tex]a_c=\frac{\left(10\right)^2}{20}[/tex]

[tex]\:a_c=\frac{100}{20}[/tex]

[tex]a_c=5[/tex] m/s²

As the truck is moving in a circle, therefore the direction is towards the center of the circle.

Hence, the magnitude and direction of the centripetal acceleration will be:

[tex]a_c=5[/tex] m/s²   (towards the center of the circle).

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