A glass flask of volume 400 cm³ is just filled with mercury at 0°C. How much mercury will overflow when the temperature of the system rises to 80°C.
The volume of mercury that overflow is 5.376 cm³
Given
volume of glass = 400 cm³
Δt=80 °C - 0 °C = 80
Required
overflow volume
Solution
With an increase in the temperature of the substance, objects can expand. This expansion includes volume expansion.
Can be formulated
[tex]\tt V_t=V_o(1+\gamma.\Delta t)\\\\\Delta V=V_o.\gamma.\Delta t[/tex]
Find volume expansion of glass and mercury
[tex]\tt \Delta V=400\times 1.2.10^{-5}.80=0.384~cm^3[/tex]
[tex]\tt \Delta V=400\times 1.8.10^{-4}\times 80=5.76~cm^3[/tex]
Overflow :
ΔV mercury - ΔV glass : 5.76-0.384 = 5.376 cm³