Answer:
The decision rule is
Reject the null hypothesis
The conclusion is
There sufficient evidence that the true mean disclosure score of all adolescents will exceed 3
Step-by-step explanation:
From the question we are told that
The sample is n = 224
The sample mean is [tex]\= x = 3.38[/tex]
The standard deviation is [tex]s = 0.98[/tex]
The population mean is [tex]\mu = 3[/tex]
The level of significance is [tex]\alpha = 0.05[/tex]
The null hypothesis is [tex]H_o : \mu = 3[/tex]
The alternative hypothesis is [tex]H_a : \mu > 3[/tex]
Generally the test statistics is mathematically represented as
[tex]z = \frac{ \= x - \mu }{ \frac{s}{ \sqrt{n} } }[/tex]
=> [tex]z = \frac{ 3.38 - 3 }{ \frac{0.98 }{ \sqrt{224} } }[/tex]
=> [tex]z = 5.80[/tex]
From the z table the area under the normal curve to the right corresponding to 5.80 is
[tex]p-value = 0[/tex]
From the value obtained we that [tex]p-value < \alpha[/tex] , hence
The decision rule is
Reject the null hypothesis
The conclusion is
There sufficient evidence that the true mean disclosure score of all adolescents will exceed 3
