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In how many ways can one write the numbers 1, 2, 3, 4, 5, and 6 in a row so that given any number in the row, all of its divisors (not including itself) appear to its left

Respuesta :

ebrightosagie

Answer:  25 ways.

Step-by-step explanation:

first we have  1,2,6. this can appear once.

4, can appear in twice.

  1. 3 can appear in-between 2 and 6, this means 3 can appear 3times before 6.
  2. 5 would appear 5 times.
  3. after 6 3 can appear 2 more times.

[tex]= (3+2) * 5\\= 5*5\\= 25ways[/tex]

by not including itself, an appearing on the left side. one number can be written 25ways

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