Answer:
[tex]y=3x+3[/tex]
Step-by-step explanation:
[tex]We\ are\ given\ that,\\-3x+y=3\\By\ adding\ both\ the\ sides\ with\ 3x\ we\ get,\\(-3x+y)+3x=(3)+3x\\Hence,\\-3x+y+3x=3x+3\\By\ cancelling\ -3x\ and\ 3x,\\y=3x+3[/tex]