Answer:
[tex]q_2=2.47\times 10^{-4}\ C[/tex]
Explanation:
The charge on one object, [tex]q_1=9.9\times 10^{-5}\ C[/tex]
The distance between the charges, r = 0.22 m
The force between the charges, F = 4,550 N
Let q₂ is the charge on the other sphere. The electrostatic force between two charges is given by the formula as follows :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\q_2=\dfrac{Fr^2}{kq_1}\\\\q_2=\dfrac{4550\times (0.22) ^2}{9\times 10^9\times 9.9\times 10^{-5}}\\\\q_2=2.47\times 10^{-4}\ C[/tex]
So, the charge on the other sphere is [tex]2.47\times 10^{-4}\ C[/tex].
