Write the equation of a parallel line that passes through (-2,-5).
y =
d. Write the equation of the perpendicular line that passes through (6, 1).
y=


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Write the equation of a parallel line that passes through 25 y d Write the equation of the perpendicular line that passes through 6 1 y PLEASEE ILL GIVE BRANLIE class=

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Answer:

There is not quite enough information but

C= y=2x-1

The equation of the line in the slope-intercept form is y=2x+5.

The slope of the parallel line is the same: m=2.

So, the equation of the parallel line is y=2x+a.

To find a, we use the fact that the line should pass through the given point: −5=(2)⋅(−2)+a.

Thus, a=−1.

Therefore, the equation of the line is y=2x−1.

D.=y= 4 - x/2

The equation of the line in the slope-intercept form is y=2x+5.

The slope of the perpendicular line is negative inverse: m=−12.

So, the equation of the perpendicular line is y=−x2+a.

To find a, we use the fact that the line should pass through the given point: 1=(−12)⋅(6)+a.

Thus, a=4.

Therefore, the equation of the line is y=4−x2.

Step-by-step explanation:

If you can give me the line that they are parallel or perpendicular to, I'll give you a more accurate answer.