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7. A student has a 25 g sample of gas in a container at STP and adds another 7

g of the gas while keeping the pressure constant, what is the new temperature in

degrees Celsius?

Respuesta :

Answer:

New temperature t2 = [1.28T− 273.15]° C

Explanation:

Given:

Volume v1 = 25 gram

New volume v2 = 25 + 7 = 32 gram

Constant pressure = p

Temperature t1 = T

Find:

New temperature t2

Computation:

Pv1/t1 = Pv2/t2

25 / T = 32 / t2

t2 = 1.28T

New temperature t2 = [1.28T− 273.15]° C

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