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Please help I will brainliest!! Really urgent!!

and tell you me how you go it, not just the answer please!❤️

This is my last ques/ of the day

Please help I will brainliest Really urgent and tell you me how you go it not just the answer please This is my last ques of the day class=

Respuesta :

Answer:    [tex]\frac{5}{6}x-10[/tex]

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Work Shown:

[tex]\left(\frac{1}{3}x-8\right)+\left(\frac{1}{2}x-2\right)\\\\\frac{1}{3}x-8+\frac{1}{2}x-2\\\\\left(\frac{1}{3}x+\frac{1}{2}x\right)+(-8-2)\\\\\left(\frac{1}{3}+\frac{1}{2}\right)x-10\\\\\left(\frac{2}{6}+\frac{3}{6}\right)x-10\\\\\frac{2+3}{6}x-10\\\\\frac{5}{6}x-10\\\\[/tex]

NgShiYin

Answer:

[tex]\frac{5}{6}[/tex]x-10

Step-by-step explanation:

([tex]\frac{1}{3}[/tex]x-8)+([tex]\frac{1}{2}[/tex]x-2) = [tex]\frac{1}{3}[/tex]x-8+[tex]\frac{1}{2}[/tex]x-2

[tex]\frac{1}{3}[/tex]x-8+[tex]\frac{1}{2}[/tex]x-2 = [tex]\frac{1}{3}[/tex]x+[tex]\frac{1}{2}[/tex]x-10

If you -8 then -2, you are subtracting 10 from the equation in total.

[tex]\frac{1}{3}[/tex]x+[tex]\frac{1}{2}[/tex]x-10 = [tex]\frac{2}{6}[/tex]x+[tex]\frac{3}{6}[/tex]x-10

To make the denominator the same, I will multiply the first fraction by 2 and the second fraction by 3 so that their denominators are 6.

[tex]\frac{2}{6}[/tex]x+[tex]\frac{3}{6}[/tex]x-10 = [tex]\frac{5}{6}[/tex]x-10

Once the denominators are the same, you can do the working for the numerators directly (2+3=5) and keep the denominator the same.

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