Electrolysis of water occurs according to the following equation...

2H20 ->2H2+O2

If electrolysis is performed with 100% efficiency on 100 grams of water. How many grams of hydrogen gas will be produced?

a. 11 grams
b. 50 grams
c. 4 grams
d. 100 grams

Respuesta :

Answer:

11.1g

Explanation:

Given parameters:

Mass of water  = 100g

Unknown:

Mass of hydrogen gas  = ?

Solution:

We need to write the balanced reaction equation first and solve from the known to the unknown;

       2H₂O  →  2H₂   +  O₂

Now, find the number of moles of the given specie;

 Number of moles of H₂O  = [tex]\frac{mass}{molar mass}[/tex]

     Molar mass of H₂O = 2(1) + 16  = 18g/mol

Number of moles  = [tex]\frac{100}{18}[/tex]  = 5.56mol

   2 mole of water produced 2 mole of hydrogen gas;

  5.56 mole of water will produce 5.56 mole of hydrogen gas

     Mass of hydrogen gas = number of moles x molar mass

    molar mass  = 2(1)  = 2g/mol

    Mass of hydrogen gas  = 2(5.56) = 11.1g