Answer:
The polynomial is x^3-x^2-33x+63
Step-by-step explanation:
Here, we want to find a polynomial of degree 3 with the given roots
-7 with a multiplicity of 1 and 3 with a multiplicity of 2
if x = -7
x + 7 is a root
if x = 3
x -3 is a root
Since the multiplicity of this is 2, we have x-3 twice
The complete polynomial is;
(x-3)(x-3)(x+7)
= x^2-6x+9(x + 7)
= x(x^2-6x+9) + 7(x^2-6x+9)
= x^3-6x^2 + 9x+7x^2-42x+63
= x^3-x^2-33x+63
