Answer:
The common difference of the given AP is d=5.
Step-by-step explanation:
Given the sequence
[tex]10,\:15,\:20[/tex]
An Arithmetic sequence has a constant difference 'd' and is defined by
[tex]a_n=a_1+\left(n-1\right)d[/tex]
Computing the common difference of all the adjacent terms
[tex]10,\:15,\:20[/tex]
[tex]15-10=5,\:\quad \:20-15=5[/tex]
As the difference between all the adjacent terms is the same and equal to
[tex]d=5[/tex]
Therefore, the common difference of the given AP is d=5.
