The empirical formula : CaAsO₄H
Further explanation
The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components
The principle of determining empirical formula
- Determine the mass ratio of the constituent elements of the compound.
- Determine the mole ratio by by dividing the percentage by the atomic mass
[tex]\tt \dfrac{22.3}{40.078}=0.556[/tex]
[tex]\tt \dfrac{41.6}{74.9246}=0.555[/tex]
[tex]\tt \dfrac{35.6}{15.9994}=2.225[/tex]
[tex]\tt \dfrac{0.56}{1.00794}=0.556[/tex]
Divide by the smallest ratio(0.555) :
Ca : As : O : H ⇒
[tex]\tt \dfrac{0.556}{0.555}\div \dfrac{0.555}{0.555}\div \dfrac{2.225}{0.555}\div \dfrac{0.556}{0.555}=1\div 1\div 4\div 1[/tex]
