Answer:
The time it takes the car to stop is 8.64 s.
Explanation:
Given;
initial velocity of the car, u = 37.3 m/s
final velocity of the car, v = 8.8 m/s
constant acceleration of the car, a = -3.3 m/s²
The time it takes the car to stop is given by;
[tex]t = \frac{v-u}{a}[/tex]
Substitute the givens;
[tex]t = \frac{v-u}{a}\\\\t = \frac{8.8-37.3}{-3.3}\\\\t = 8.64 \ s[/tex]
Therefore, the time it takes the car to stop is 8.64 s.
