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If 2.00 moles of H₂ and 1.55 moles of O₂ react how many moles of H₂O can be produced in the reaction below?
2 H₂(g) + O₂(g) → 2 H₂O(g)

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Answer:

2 mol H₂O

Explanation:

With the reaction,

  • 2H₂(g) + O₂(g) → 2 H₂O(g)

1.55 moles of O₂ would react completely with ( 2*1.55 ) 3.1 moles of H₂. There are not as many moles of H₂, thus H₂ is the limiting reactant.

Now we calculate the moles of H₂O produced, starting from the moles of limiting reactant:

  • 2.00 mol H₂  * [tex]\frac{2molH_2O}{2mol H_2}[/tex] = 2 mol H₂O

The number of moles of H₂O that could be produced in the reaction is 2.00 moles

From the question,

We are to determine the number of moles of H₂O that could be produced.

The given balanced chemical equation is

2 H₂(g) + O₂(g) → 2 H₂O(g)

This means,

2 moles of H₂(g) reacts with 1 mole of O₂(g) to produce 2 moles of H₂O

From the given information

Number of moles of H₂ present = 2.00 moles

and

Number of moles of O₂ present = 1.55 moles

Since,

2 moles of H₂(g) reacts with 1 mole of O₂(g) to produce 2 moles of H₂O

Then,

The 2.00 moles of H₂(g) will react with 1.00 mole of O₂(g) to produce 2.00 moles of H₂O

∴ 2.00 moles of H₂O will be produced during the reaction

(NOTE: Only 1.00 mole of the O₂(g) will react, meaning O₂(g) is the excess reactant)

Hence, the number of moles of H₂O that could be produced in the reaction is 2.00 moles

Learn more here: https://brainly.com/question/1553639

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