Calcium sulfide has a face-centered cubic unit cell with calcium ions in octahedral holes and sulfide ions at the lattice points. How many ions of each element are contained in each unit cell

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Answer:

4 calcium ions and 4 sulfide ions.

Explanation:

In a face centered unit cell, 8 corners of the unit cell are occupied by 8 atoms. Each corner is 1/8 of a cell. In addition it has 6 atoms in the face of the lattice, which is 1/2 of a cell. (1/8 * 8) + (1/2 * 6) = 4. CaS has a 1:1 ratio. Therefore, they each have 4 ions.

Each cubic unit cell contains FOUR (4) calcium ions in octahedral holes and FOUR (4) sulfide ions at the lattice points.

  • Calcium sulfide is a solid inorganic compound (chemical formula: CaS) that shows a white appearance and crystallizes in cubes like rock salts.

  • This molecule (calcium sulfide) is widely used to produce certain classes of paints, ceramics, paper, etc.

  • Calcium has a valence of 2 electrons, while sulfur has '6' valence electrons, thereby the number of valence electrons in CaS is equal to 2 + 6 = 8.

  • Calcium sulfide (CaS) adopts a sodium chloride crystal structure where each CaS unit cell contains four sulfide (S²⁻) ions and four calcium (Ca²⁻) ions.

In conclusion, each cubic unit cell contains FOUR (4) calcium ions in octahedral holes and FOUR (4) sulfide ions at the lattice points.

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