A building wall consists of 12-in clay brick and 1/2-in. Fiberboard on one side. If the wall is 10 ft high, determine the load in pounds per foot that it exerts on the floor.

Respuesta :

Answer:

1.16 k/ft

Explanation:

From the given information;

Using table 1.3 for Minimum design dead loads;

For 12-in clay brick,

the obtained min. design dead load = 115 psf

For Fiberboard 1/2 in. ceilings, the minimum design dead load is 0.75 psf

To start with the load that is being exerted on the floor as a result of the clay brick wall ([tex]L_1[/tex] ), we have:

[tex]L_1 = Load \times h[/tex]

[tex]L_1 = 115 \times 10[/tex]

[tex]L_1 = 1150 \ lb/ft[/tex]

To calculate the load exerted on the floor as a result of the 1/2 fireboard, we have:

[tex]L_2 = Load \times h[/tex]

[tex]L_2 = 0.75 \times 10[/tex]

[tex]L_2 = 7.5 \ lb/ft[/tex]

The total load exerted on the floor = [tex]L_1 + L_2[/tex]

The total load exerted on the floor = 1150 + 7.50

The total load exerted on the floor = 1157.50 lb/ft

To (k/ft), we get:

[tex]= 1157.50 \ lb/ft \times \dfrac{1 \ k}{1000 \ lb}[/tex]

= 1.157 k/ft

≅ 1.16 k/ft