Answer:
The three integers whose three times the sum of three consecutive integers is 72 will be: 7, 8, 9
Step-by-step explanation:
Let x, y, and z be the three consecutive integers
The sum of x, y, and z will be: x+y+z
The three times the sum of three consecutive integers is 72.
so the equation becomes:
3(x+y+z)=72
Now, putting x = 7, y=8 and z=9 in the L.H.S equation to check
3(x+y+z)
⇒ 3(7+8+9)
⇒ 3(24)
⇒ 72
Therefore, it is clear that the three integers whose three times the sum of three consecutive integers is 72 will be: 7, 8, 9
