Answer:
AE:[tex]\sqrt{15300}[/tex]
DE:150
PABCDE: 720
Step-by-step explanation:
We can find AE by the pythagorean theorem, [tex]a^{2}+b^{2}=c^{2}[/tex]
AE is the hypotenuse so AE=c, and the leg of the triangle would be 150-30=120
[tex]50^{2}+120^{2}=c^{2}[/tex]
c^2=2500+14400
AE=130
We can use the pythagorean theorem again to find DE.
The base would equal 140-50=90 and the height would equal 120
[tex]90^{2} +120^{2} =DE^{2}[/tex]
DE^2=22500
DE=150
The perimeter would be 150+140+150+130+150=720
Let me know if somethings wrong
