Answer:
[tex]\huge\boxed{\sf T = 2.04\ secs}[/tex]
Explanation:
Given Data:
Initial Velocity = [tex]\sf V_{i}[/tex] = 20 m/s
Angle = [tex]\sf \theta[/tex] = 30°
Acceleration due to gravity = g = 9.8 m/s²
Required:
Time of flight = T = ?
Formula:
[tex]\sf T = \frac{2\ V_{i}\ sin\theta}{g}[/tex]
Solution:
Putting values in the above formula
T = 2(20)sin 30 / 9.8
T = 40 (0.5) / 9.8
T = 20 / 9.8
T = 2.04 secs
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AnonymousHelper1807
