There are 0.213 moles of FeF3 present in 24 grams.
It is a standard scientific unit for determining the large quantities of very small entities like molecules, atoms, or other particular particles.
Based on the given information:
Now the molar mass of FeF3 is,
[tex]= (1*55.84+3*19)g/mol\\= (55.84+57.00) g/mol\\= 112.84 g/mol[/tex]
The formula to find the number of moles of FeF3 is,
[tex]Number of moles = \frac{Mass}{Molecular mass}[/tex]
Now putting the values we get,
[tex]Number of moles = \frac{24 grams}{112.84 g/mol} \\Number of moles = 0.213 moles[/tex]
Thus, the number of moles in 24 grams of FeF3 is 0.213 moles.
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https://brainly.com/question/14464650
The number of moles in 24.0 grams should be 0.213 moles.
We know that
Number of moles = mass ÷relative mass
Here
Mass be 24
And, the relative mass should be
= 55.8 + 19 + 19 + 19
= 112.8 g/mol
So the no of moles should be
[tex]= 24 \div 112.8[/tex]
= 0.213 moles
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