Answer:
98 m/s.
Explanation:
In this problem, we need to find the speed of a jumper 10 seconds after jumping. Initially, the bungee jumper was at rest. Let v is the speed after 10 s. Using first equation of motion.
v = u +at
Here, u = 0 and a = g
v = gt
v = (9.8 m/s)(10 s)
v = 98 m/s
So, the speed of a jumper 10 seconds after jumping is 98 m/s.
