Answer:
0.63m/s²
Explanation:
The average acceleration can be derived from using the formula:
V = u + at
Where v = final velocity (m/s)
u = initial velocity (m/s)
a = acceleration (m/s²)
t = time (s)
V = u + at
V - u = at
a = v - u/t
a = ∆V/t
According to the provided information; v = 5.8m/s, u = 0m/s, t = 9.25s
a = ∆V/t
a = (5.8-0)/9.25
a = 5.8/9.25
a = 0.627
a = 0.63m/s²
Hence, the average acceleration is 0.63m/s²
The average acceleration of the ferry which leaves Guemes Island and heads back toward Anacortes is 0.627m/s².
Given the data in the question;
To determine the average acceleration, we use the first equation of motion:
[tex]v = u + at[/tex]
Where v is final speed, u is initial speed, a is acceleration and t is time taken.
We substitute our given values into the equation
[tex]5.8m/s = 0 + [ a * 9.25s ]\\\\5.8m/s = a * 9.25s\\\\a = \frac{5.8m/s}{9.25s}\\\\a = 0.627m/s^2[/tex]
Therefore, the average acceleration of the ferry which leaves Guemes Island and heads back toward Anacortes is 0.627m/s².
