Respuesta :
Given:
Newton has 10 more dimes than nickels.
He has twice the number of quarters than nickels.
Total amount he has = $6.20.
To find:
The number of each coin.
Solution:
Let the number of nickels be x.
Newton has 10 more dimes than nickels.
Dimes = x+10
He has twice the number of quarters than nickels.
Quarters = 2x
We know that, 1 nickel = $0.05, 1 dime = $0.10 and 1 quarter = $0.25.
Total amount he has is $6.20.
[tex]x\times 0.05+(x+10)\times 0.10+2x\times 0.25=6.20[/tex]
[tex]0.05x+0.10x+1+0.50x=6.20[/tex]
[tex]0.65x=6.20-1[/tex]
[tex]0.65x=5.20[/tex]
Divide both sides by 0.65.
[tex]x=\dfrac{5.20}{0.65}[/tex]
[tex]x=8[/tex]
Now,
Number of nickels = 8
Number of dimes = 8 + 10 = 18
Number of quarters = 2(8) = 16
Therefore, the number of nickels, dimes and quarters are 8, 18 and 16 respectively.
