A parachute on a racing dragster opens and changes the speed of the car from 79.33 m/sec to 41.55 m/sec in a period of 5.21 seconds. What is the acceleration of the dragster?

Answer:
c: -7.25
Explanation:
Here we can use the equation v=u+at
Where v is the final velocity
u is the initial velocity
a is acceleration
and t is time
41.55=79.33+a(5.21)
41.55-79.33=5.21a
-37.78=5.21a
a=-7.25 m/[tex]s^2[/tex]
The negative sign is due to the fact that they are slowing down