Answer:
13 dogs and 15 cats
Step-by-step explanation:
d= number of dogs, c= number of cats
First make you linear system of two equations like so:
100d+45c=1975 (100 dollars times an unknown amount of dogs plus 45 times an unknown amount of cats equals $1975)
d+c=28 (A certain amount of cats plus a certain amount of dogs has a total of 28 pets)
100d+45c=1975
d+c=28
We are going to solve using elimination
100d+45c=1975
-100(d+c=28)
100d+45c=1975
-100d-100c=-2800
+______________
-55c=-825
55c=825
c=15
There were 15 cats sold
Now you will plug it in to an original equation to solve for the amount of dogs
d+c=28
d+15=28
d=13
There were 13 dogs
