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A combination lock is opened with the correct sequence of three numbers between 0 and 49 inclusive. If a number can be used more than​ once, what is the probability of guessing those three numbers and opening the lock with the first​ try? ​ (Write answer as a simplified​ fraction

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Answer:

125,000

Step-by-step explanation:

Given that :

Sequence of three numbers chosen from 0 to 49 inclusive

Since numbers can be repeated ; hence numbers do not have to be different ;

Number of digits between (0 - 49 inclusive) = 50 digits.

Thus, there are equal number of possible choices for each of the three numbers, which is equal to the Number of digits :

1st number = 50

2nd = 50

3rd = 50

Hence,

(50³). = 50 * 50 * 50 = 125,000

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