Answer:
Step-by-step explanation:
let the height of a kicked soccer ball be expressed by the function:
h(t) = -16t^2 + 24t + 1 where t is in seconds
The ball hit the cross bar when the height is zero
The equation becomes
0 = -16t^2 + 24t + 1
16t^2 - 24t - 1= 0
t = 24±√24²-4(16)(-1)/2(16)
t = 24±√576+64/32
t = 24±√640/32
t = 24+25.298/32
t = 49.298/32
t = 1.54 secs
Hence the ball hit the cross bar at t = 1.6secs (to the nearest tenth)
