Answer:
The bomb will land at approximately 3.5 Km
Explanation:
Horizontal Motion
The bomb is thrown horizontally by an airplane with a speed v=50 m/s from a height h=25,000. The range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
[tex]\displaystyle d=50\cdot\sqrt{\frac {2*25,000}{9.8}}[/tex]
[tex]\displaystyle d=3,571.43\ m[/tex]
The bomb will land at approximately 3.5 Km
