Answer:
Step-by-step explanation:
Perpendicular lines have the relationship that their slope is the negative reciprocal of the other's.
in this case, the other line's slope is [tex]\frac{-1}{3}[/tex]
we can use (6, -1) to solve the rest
[tex]y = mx + b\\y = \frac{-x}{3} + b\\-1 = \frac{-6}{3}+ b\\-1 = -2 + b\\b = 1\\y = \frac{-1}{3} (x) + 1[/tex]