Answer:
[tex]x^2+4x+2[/tex]
Step-by-step explanation:
[tex]\frac{2x^3+11x^2+16x+6}{2x+3}\\\\Factorize \: :\\2x^3+11x^2+16x+6 : \:\left(2x+3\right)\left(x^2+4x+2\right) \\\\=\frac{\left(2x+3\right)\left(x^2+4x+2\right)}{2x+3}\\\\\mathrm{Cancel\:the\:common\:factor:}\:2x+3\\\\=x^2+4x+2[/tex]
I hope it helps .
